A Carnot engine takes heat from a reservoir at 627° C and rejects heat to a sink at 27° C . Its efficiency will be

Question

A Carnot engine takes heat from a reservoir at 627° C and rejects heat to a sink at 27° C . Its efficiency will be (A) 3/5 (B) 1/3 (C) 2/3 (D) 200/209

Tardigrade Admin · Accepted Answer

η =1-(T2/T1) ∴ η =1-((27+273)/(273+627)) =1-(300/900)=(600/900)=(2/3)

Q. A Carnot engine takes heat from a reservoir at $627^{\circ} C$ and rejects heat to a sink at $27^{\circ} C$ . Its efficiency will be

3/5

1/3

2/3

200/209

$η = 1 - \frac{T _{2}}{T _{1}}$ $∴$ $η = 1 - \frac{( 27 + 273 )}{( 273 + 627 )}$ $= 1 - \frac{300}{900} = \frac{600}{900} = \frac{2}{3}$

Q. A Carnot engine takes heat from a reservoir at 627∘C and rejects heat to a sink at 27∘C . Its efficiency will be

3/5

1/3

2/3

200/209

η=1−T1​T2​​ ∴ η=1−(273+627)(27+273)​ =1−900300​=900600​=32​

Q. A Carnot engine takes heat from a reservoir at $627^{\circ} C$ and rejects heat to a sink at $27^{\circ} C$ . Its efficiency will be

$η = 1 - \frac{T _{2}}{T _{1}}$ $∴$ $η = 1 - \frac{( 27 + 273 )}{( 273 + 627 )}$ $= 1 - \frac{300}{900} = \frac{600}{900} = \frac{2}{3}$