Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Physics
A carnot engine takes 3 × 106 cal of heat from a reservoir at 627°C, and gives it to a sink at 27°C. The work done by the engine is
Q. A carnot engine takes
3
×
1
0
6
cal of heat from a reservoir at
62
7
°
C
, and gives it to a sink at
2
7
°
C
. The work done by the engine is
1880
178
AIEEE
AIEEE 2003
Thermodynamics
Report Error
A
4.2
×
1
0
6
J
36%
B
8.4
×
1
0
6
J
27%
C
16.8
×
1
0
6
J
18%
D
zero
18%
Solution:
Work done by the engine while taking heat
Q
=
3
×
1
0
6
cal is
W
=
2
×
1
0
6
×
4.2
=
8.4
×
1
0
6
J
.