Question

A Carnot engine has same efficiency between (i) $100K$ and $500K$, (ii) $TK$ and $900K$. The value of $T$ is

• A. 180 K
• B. 90 K
• C. 270 K
• D. 360 K

Answer 1

Answer: (A)

As, $\eta =1-\frac{T_2}{T_1}$
$\Rightarrow 1-\frac{100}{500}=1-\frac{T}{900}$
$\therefore \frac{T}{900}=\frac{1}{5}$
Or $T=180K$