A carbon resistor of (47 ± 4.7) k Ω is to be marked with rings of different colours for its identification. The colour code sequence will be

Question

A carbon resistor of (47 ± 4.7) k Ω is to be marked with rings of different colours for its identification. The colour code sequence will be (A) Green - Orange- Violet- Gold (B) Violet - Yellow - Orange - Silver (C) Yellow - Green - Violet - Gold (D) Yellow - Violet - Orange - Silver

Tardigrade Admin · Accepted Answer

(47 ± 4.7) k Ω = 47 × 103 ± 10 % ∴ Yellow - Violet - Orange - Silver

Q. A carbon resistor of $(47 \pm 4.7) k Ω$ is to be marked with rings of different colours for its identification. The colour code sequence will be

Green - Orange- Violet- Gold

Violet - Yellow - Orange - Silver

Yellow - Green - Violet - Gold

Yellow - Violet - Orange - Silver

$(47 \pm 4.7) k Ω = 47 \times 1 0^{3} \pm 10%$
$∴$ Yellow - Violet - Orange - Silver

Q. A carbon resistor of (47±4.7)kΩ is to be marked with rings of different colours for its identification. The colour code sequence will be