A carbon compound containing carbon and oxygen has approximate molar mass equal to 290 . On analysis it is found to contain 50 % by mass of each element. Therefore, molecular formula of the compound is:

Question

A carbon compound containing carbon and oxygen has approximate molar mass equal to 290 . On analysis it is found to contain 50 % by mass of each element. Therefore, molecular formula of the compound is: (A) C 12 O 9 (B) C 4 O 3 (C) C 3 O 4 (D) C 9 O 12

Tardigrade Admin · Accepted Answer

Element C O % by mass 50 50 Ratio by no. of atoms: 50 50 12 16 Simplest ratio by no of atoms: 4: 3 ∴ Empirical formula = C 4 O 3 And let molecular formula be ( C 4 O 3)n ∴ 96 n=290 or n=(290/96) ≃ 3 ∴ Molecular formula is C 12 O 9

Q. A carbon compound containing carbon and oxygen has approximate molar mass equal to $290$ . On analysis it is found to contain $50%$ by mass of each element. Therefore, molecular formula of the compound is:

$C_{12} O_{9}$

$C_{4} O_{3}$

$C_{3} O_{4}$

$C_{9} O_{12}$

Element C O

$%$ by mass 50 50

Ratio by no. of atoms: 50 50

12 16

Simplest ratio by no of atoms : $4 : 3$
$∴$ Empirical formula $= C_{4} O_{3}$
And let molecular formula be $(C_{4} O_{3})_{n}$
$∴ 96 n = 290$
or $n = \frac{290}{96} ≃ 3$
$∴$ Molecular formula is $C_{12} O_{9}$

Q. A carbon compound containing carbon and oxygen has approximate molar mass equal to 290 . On analysis it is found to contain 50% by mass of each element. Therefore, molecular formula of the compound is:

C12​O9​

C4​O3​

C3​O4​

C9​O12​