A car travels a distance of ' x ' with speed v1 and then same distance ' x ' with speed v2 in the same direction. The average speed of the car is:

Question

A car travels a distance of ' x ' with speed v1 and then same distance ' x ' with speed v2 in the same direction. The average speed of the car is: (A) (v1 v2/2(v1+v2)) (B) (2 x/v1+v2) (C) (2 v1 v2/v1+v2) (D) (v1+v2/2)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/2bffa61ca3a8ad1ae18ad67f6cbe80d4-.png" /> Average velocity =( text Total displacement / text Total time ) =( x + x /( x ) v 1+( x ) v 2=(2 v 1 v 2/ v 1+ v 2)

Q. A car travels a distance of ' $x$ ' with speed $v_{1}$ and then same distance ' $x$ ' with speed $v_{2}$ in the same direction. The average speed of the car is:

$\frac{v _{1} v _{2}}{2 ( v _{1} + v _{2} )}$

$\frac{2 x}{v _{1} + v _{2}}$

$\frac{2 v _{1} v _{2}}{v _{1} + v _{2}}$

$\frac{v _{1} + v _{2}}{2}$

Average velocity $= \frac{Total displacement}{Total time}$
$= \frac{x + x}{\frac{x}{v _{1}} + \frac{x}{v _{2}}} = \frac{2 v _{1} v _{2}}{v _{1} + v _{2}}$

Q. A car travels a distance of ' x ' with speed v1​ and then same distance ' x ' with speed v2​ in the same direction. The average speed of the car is:

2(v1​+v2​)v1​v2​​

v1​+v2​2x​

v1​+v2​2v1​v2​​

2v1​+v2​​