A car travelling at a speed of 30 km/hr is brought to a halt is 8 m by applying brakes. If the same car is travelling at 60 km/hr it can be brought to a halt with the same braking force in:

Question

A car travelling at a speed of 30 km/hr is brought to a halt is 8 m by applying brakes. If the same car is travelling at 60 km/hr it can be brought to a halt with the same braking force in: (A) 8 m (B) 16 m (C) 24 m (D) 32 m

Tardigrade Admin · Accepted Answer

( S 1/ S 2)=( V 12/ V 22) stopping distance ((8/ S 2))=((30/60))2 S 2=32 m

Q. A car travelling at a speed of $30 km / h r$ is brought to a halt is $8 m$ by applying brakes. If the same car is travelling at $60 km / h r$ it can be brought to a halt with the same braking force in:

8 m

16 m

24 m

32 m

$\frac{S _{1}}{S _{2}} = \frac{V _{1}^{2}}{V _{2}^{2}}$ stopping distance
$(\frac{8}{S _{2}}) = (\frac{30}{60})^{2}$
$S_{2} = 32 m$

Q. A car travelling at a speed of 30km/hr is brought to a halt is 8m by applying brakes. If the same car is travelling at 60km/hr it can be brought to a halt with the same braking force in:

8 m

16 m

24 m

32 m

S2​S1​​=V22​V12​​ stopping distance (S2​8​)=(6030​)2 S2​=32m

Q. A car travelling at a speed of $30 km / h r$ is brought to a halt is $8 m$ by applying brakes. If the same car is travelling at $60 km / h r$ it can be brought to a halt with the same braking force in:

$\frac{S _{1}}{S _{2}} = \frac{V _{1}^{2}}{V _{2}^{2}}$ stopping distance
$(\frac{8}{S _{2}}) = (\frac{30}{60})^{2}$
$S_{2} = 32 m$