A car starts from rest and accelerates uniformly to a speed of 180 km/h in 10 s. The distance covered by the car in this time interval is

Question

A car starts from rest and accelerates uniformly to a speed of 180 km/h in 10 s. The distance covered by the car in this time interval is (A) 500 m (B) 250 m (C) 100 m (D) 200 m

Tardigrade Admin · Accepted Answer

Speed, v = 180 kmh-1 =50 ms -1 times t =10s sence Acceleration of the car a =(v-u/t)=(50-0/10) 5 ms-2 Thus the distance covered by the car S=(1/2)at2=(1/2)× 5× (10)2 =250 m

Q. A car starts from rest and accelerates uniformly to a speed of $180 km / h$ in $10 s$ . The distance covered by the car in this time interval is

500 m

250 m

100 m

200 m

Speed, v = 180 $km h^{- 1}$ =50 $m s^{- 1}$ times t =10s
sence Acceleration of the car a = $\frac{v - u}{t} = \frac{50 - 0}{10}$
$5 m s^{- 2}$
Thus the distance covered by the car
$S = \frac{1}{2} a t^{2} = \frac{1}{2} \times 5 \times (10)^{2}$ =250 m

Q. A car starts from rest and accelerates uniformly to a speed of 180km/h in 10s. The distance covered by the car in this time interval is