A car starts from rest and accelerates uniformly to a speed of 18 km h-1 in 10. The distance covered by the car in the time interval is

Question

A car starts from rest and accelerates uniformly to a speed of 18 km h-1 in 10. The distance covered by the car in the time interval is (A) 200 m (B) 300 m (C) 500 m (D) 250 m

Tardigrade Admin · Accepted Answer

u=0, v=180 km / h =50 m / s Time taken, t =10 s a=(v-u/t)=(50/10)=5 ms -2 Distance covered s=u t+(1/2) a t2 =0+(1/2) × 5 ×(10)2 =(500/2) ⇒ =250 m

Q. A car starts from rest and accelerates uniformly to a speed of $18 km h^{- 1}$ in $10$ . The distance covered by the car in the time interval is

200 m

300 m

500 m

250 m

$u = 0, v = 180 km / h = 50 m / s$
Time taken, $t = 10 s$
$a = \frac{v - u}{t} = \frac{50}{10} = 5 m s^{- 2}$
Distance covered $s = u t + \frac{1}{2} a t^{2}$
$= 0 + \frac{1}{2} \times 5 \times (10)^{2}$
$= \frac{500}{2}$
$\Rightarrow= 250 m$

Q. A car starts from rest and accelerates uniformly to a speed of 18kmh−1 in 10. The distance covered by the car in the time interval is