A car of mass 1000 kg travelling at a speed of 72 km/h hits a tree and comes to rest in 0.2 s. The average force on the car during the impact is

Question

A car of mass 1000 kg travelling at a speed of 72 km/h hits a tree and comes to rest in 0.2 s. The average force on the car during the impact is (A)  36× 104N  (B)  1× 105N  (C)  36× 107N  (D)  36× 105N

Tardigrade Admin · Accepted Answer

Given, m=1000 kg, v=72 km/h and Δ t=0.2 s ∴ Fav=(mvav/Δ t) =(1000× 20× 10/0.2) =1× 105N

Q. A car of mass 1000 kg travelling at a speed of 72 km/h hits a tree and comes to rest in 0.2 s. The average force on the car during the impact is

$36 \times 10^{4} N$

$1 \times 10^{5} N$

$36 \times 10^{7} N$

$36 \times 10^{5} N$

Given, $m = 1000 k g, v = 72 km / h$ and $Δ t = 0.2 s$ $∴$ $F_{a v} = \frac{m v _{a v}}{Δ t}$ $= \frac{1000 \times 20 \times 10}{0.2}$ $= 1 \times 10^{5} N$

Q. A car of mass 1000 kg travelling at a speed of 72 km/h hits a tree and comes to rest in 0.2 s. The average force on the car during the impact is

36×104N

1×105N

36×107N

36×105N

Given, m=1000kg,v=72km/h and Δt=0.2s ∴ Fav​=Δtmvav​​ =0.21000×20×10​ =1×105N

$36 \times 10^{4} N$

$1 \times 10^{5} N$

$36 \times 10^{7} N$

$36 \times 10^{5} N$

Given, $m = 1000 k g, v = 72 km / h$ and $Δ t = 0.2 s$ $∴$ $F_{a v} = \frac{m v _{a v}}{Δ t}$ $= \frac{1000 \times 20 \times 10}{0.2}$ $= 1 \times 10^{5} N$