A car moves a distance of 200 m. It covers the first half of the distance at speed 40 km/h and the second half of distance at speed v (km/h). The average speed is 48 km/h. Find the value of v

Question

A car moves a distance of 200 m. It covers the first half of the distance at speed 40 km/h and the second half of distance at speed v (km/h). The average speed is 48 km/h. Find the value of v (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

48 = (200×10-3/((100×10-3)40)+((100×10-3)v) or v = 60 km/h

Q. A car moves a distance of $200 m$ . It covers the first half of the distance at speed $40 km / h$ and the second half of distance at speed $v (km / h)$ . The average speed is $48 km / h$ . Find the value of $v$

$48 = \frac{200 \times 1 0 ^{- 3}}{( \frac{100 \times 1 0 ^{- 3}}{40} ) + ( \frac{100 \times 1 0 ^{- 3}}{v} )}$
or $v = 60 km / h$

Q. A car moves a distance of 200m. It covers the first half of the distance at speed 40km/h and the second half of distance at speed v(km/h). The average speed is 48km/h. Find the value of v

48=(40100×10−3​)+(v100×10−3​)200×10−3​ or v=60km/h

Q. A car moves a distance of $200 m$ . It covers the first half of the distance at speed $40 km / h$ and the second half of distance at speed $v (km / h)$ . The average speed is $48 km / h$ . Find the value of $v$

$48 = \frac{200 \times 1 0 ^{- 3}}{( \frac{100 \times 1 0 ^{- 3}}{40} ) + ( \frac{100 \times 1 0 ^{- 3}}{v} )}$
or $v = 60 km / h$