A car is moving with a velocity 8m/sec whose mass is 150 kg. To stop it in (1/5) sec, the required force in opposite direction is

Question

A car is moving with a velocity 8m/sec whose mass is 150 kg. To stop it in (1/5) sec, the required force in opposite direction is (A) 300 N (B) 100 N (C) 200 N (D) 6000 N

Tardigrade Admin · Accepted Answer

F=m((d v/d t)) (second law of motion) F=150((8/0.2)) =150 × 40=6000 mathrm~N

Q. A car is moving with a velocity $8 m / sec$ whose mass is $150 k g$ . To stop it in $\frac{1}{5}$ sec, the required force in opposite direction is

300 N

100 N

200 N

6000 N

$F = m (\frac{d v}{d t})$ (second law of motion)
$F = 150 (\frac{8}{0.2})$
$= 150 \times 40 = 6000 N$

Q. A car is moving with a velocity 8m/sec whose mass is 150kg. To stop it in 51​ sec, the required force in opposite direction is