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  4. A car is moving with a velocity 8m/sec whose mass is 150 kg. To stop it in (1/5) sec, the required force in opposite direction is

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Q. A car is moving with a velocity $8m/sec$ whose mass is $150 \,kg$. To stop it in $\frac{1}{5}$ sec, the required force in opposite direction is

Laws of Motion

Solution:

$F=m\left(\frac{d v}{d t}\right)$ (second law of motion)
$F=150\left(\frac{8}{0.2}\right)$
$=150 \times 40=6000 \mathrm{~N}$