A car is moving on a circular level road of curvature 300 m. If the coefficient of friction is 0.3 and acceleration due to gravity is 10 m s-2, the maximum speed of the car can be

Question

A car is moving on a circular level road of curvature 300 m. If the coefficient of friction is 0.3 and acceleration due to gravity is 10 m s-2, the maximum speed of the car can be (A) 90 km h-1 (B) 81 km h-1 (C) 108 km h-1 (D) 162 km h-1

Tardigrade Admin · Accepted Answer

Here, R = 300 m, m = 0.3, g = 10 m s-2 The maximum speed of the car is upsilonmax=√μ Rg=√0.3×300 m×10 m s-2 =30 m s-1=30×(18/5)km h-1=108 km h-1

Q. A car is moving on a circular level road of curvature 300 m. If the coefficient of friction is $0.3$ and acceleration due to gravity is $10 m s^{- 2}$ , the maximum speed of the car can be

$90 km h^{- 1}$

$81 km h^{- 1}$

$108 km h^{- 1}$

$162 km h^{- 1}$

Here, $R = 300 m, m = 0.3, g = 10 m s^{- 2}$
The maximum speed of the car is
$υ_{ma x} = μ R g = 0.3 \times 300 m \times 10 m s^{- 2}$
$= 30 m s^{- 1} = 30 \times \frac{18}{5} km h^{- 1} = 108 km h^{- 1}$

Q. A car is moving on a circular level road of curvature 300 m. If the coefficient of friction is 0.3 and acceleration due to gravity is 10ms−2, the maximum speed of the car can be

90kmh−1

81kmh−1

108kmh−1

162kmh−1