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Q. A car is moving on a circular level road of curvature 300 m. If the coefficient of friction is $0.3$ and acceleration due to gravity is $10\,m\, s^{-2}$, the maximum speed of the car can be

Laws of Motion

Solution:

Here, $R = 300 \,m, m = 0.3, g = 10 \,m \,s^{-2}$
The maximum speed of the car is
$\upsilon_{max}=\sqrt{\mu\,Rg}=\sqrt{0.3\times300\,m\times10\,m\,s^{-2}}$
$=30\,m\,s^{-1}=30\times\frac{18}{5}km\,h^{-1}=108\,km\,h^{-1}$