A car is moving in a circular horizontal track of radius 10 m with a constant speed of 10 ms -1. A bob is suspended from the roof of the car by a light wire of length 1.0 m. The angle made by the wire with the vertical is (in radian)

Question

A car is moving in a circular horizontal track of radius 10 m with a constant speed of 10 ms -1. A bob is suspended from the roof of the car by a light wire of length 1.0 m. The angle made by the wire with the vertical is (in radian) (A) 0 (B) (π/3) (C) (π/6) (D) (π/4)

Tardigrade Admin · Accepted Answer

tan θ=(V2/2 g)=(10 × 10/10 × 10)=1 θ=(π/4)

Q. A car is moving in a circular horizontal track of radius $10 m$ with a constant speed of $10 m s^{- 1}$ . A bob is suspended from the roof of the car by a light wire of length $1.0 m$ . The angle made by the wire with the vertical is (in radian)

$0$

$\frac{π}{3}$

$\frac{π}{6}$

$\frac{π}{4}$

$tan θ = \frac{V ^{2}}{2 g} = \frac{10 \times 10}{10 \times 10} = 1$
$θ = \frac{π}{4}$

Q. A car is moving in a circular horizontal track of radius 10m with a constant speed of 10ms−1. A bob is suspended from the roof of the car by a light wire of length 1.0m. The angle made by the wire with the vertical is (in radian)

0

3π​

6π​

4π​

tanθ=2gV2​=10×1010×10​=1 θ=4π​

Q. A car is moving in a circular horizontal track of radius $10 m$ with a constant speed of $10 m s^{- 1}$ . A bob is suspended from the roof of the car by a light wire of length $1.0 m$ . The angle made by the wire with the vertical is (in radian)

$0$

$\frac{π}{3}$

$\frac{π}{6}$

$\frac{π}{4}$

$tan θ = \frac{V ^{2}}{2 g} = \frac{10 \times 10}{10 \times 10} = 1$
$θ = \frac{π}{4}$