A capillary tube of radius r can support a liquid of weight 6.28 × 10-4 N. If the surface tension of the liquid is 5 × 10-2 N / m. The radius of capillary must be

Question

A capillary tube of radius r can support a liquid of weight 6.28 × 10-4 N. If the surface tension of the liquid is 5 × 10-2 N / m. The radius of capillary must be (A) 2.0 × 10-3 m (B) 20 × 10-4 m (C) 1.5 × 10-3 m (D) 12.5 × 10-4 m

Tardigrade Admin · Accepted Answer

W=T . 2 π r r =(W/2 π T)=(6.28 × 10-4/2 × 3.14 × 5 × 10-2) =2 × 10-3 m

Q. A capillary tube of radius $r$ can support a liquid of weight $6.28 \times 1 0^{- 4} N$ . If the surface tension of the liquid is $5 \times 1 0^{- 2} N / m$ . The radius of capillary must be

$2.0 \times 1 0^{- 3} m$

$20 \times 1 0^{- 4} m$

$1.5 \times 1 0^{- 3} m$

$12.5 \times 1 0^{- 4} m$

$W = T .2 π r$
$r = \frac{W}{2 π T} = \frac{6.28 \times 1 0 ^{- 4}}{2 \times 3.14 \times 5 \times 1 0 ^{- 2}}$
$= 2 \times 1 0^{- 3} m$

Q. A capillary tube of radius r can support a liquid of weight 6.28×10−4N. If the surface tension of the liquid is 5×10−2N/m. The radius of capillary must be

2.0×10−3m

20×10−4m

1.5×10−3m

12.5×10−4m