A capacitor of capacity C1 is charged upto V volt and then connected to an uncharged capacitor of capacity C 2. Then final potential difference across each will be

Question

A capacitor of capacity C1 is charged upto V volt and then connected to an uncharged capacitor of capacity C 2. Then final potential difference across each will be (A) ( C 1 V 1+ C 2 V 2/ C 1+ C 2) (B) (( C 1/ C 1+ C 2)) V (C) C1+2 C2 (D) ((C1+C2/C1 C2)) V

Tardigrade Admin · Accepted Answer

C 2 capacitor is uncharged capacitor that means potential difference across it is zero because capacity can't be zero C =(ε0 A / d ), q = CV then potential difference will be V '=( C 1 V 1+ C 2 V 2/ C 1+ C 2) V 2=0, V 1= V then, V '=( C 1 V + C 2(0)/ C 1+ C 2) V '=(( C 1/ C 1+ C 2)) V

Q. A capacitor of capacity $C_{1}$ is charged upto $V$ volt and then connected to an uncharged capacitor of capacity $C_{2}$ . Then final potential difference across each will be

$\frac{C _{1} V _{1} + C _{2} V _{2}}{C _{1} + C _{2}}$

$(\frac{C _{1}}{C _{1} + C _{2}}) V$

$C_{1} + 2 C_{2}$

$(\frac{C _{1} + C _{2}}{C _{1} C _{2}}) V$

Q. A capacitor of capacity C1​ is charged upto V volt and then connected to an uncharged capacitor of capacity C2​. Then final potential difference across each will be

C1​+C2​C1​V1​+C2​V2​​

(C1​+C2​C1​​)V

C1​+2C2​

(C1​C2​C1​+C2​​)V

C2​ capacitor is uncharged capacitor that means potential difference across it is zero because capacity can't be zero C=dε0​A​,q=CV then potential difference will be V′=C1​+C2​C1​V1​+C2​V2​​ V2​=0,V1​=V then, V′=C1​+C2​C1​V+C2​(0)​ V′=(C1​+C2​C1​​)V

Q. A capacitor of capacity $C_{1}$ is charged upto $V$ volt and then connected to an uncharged capacitor of capacity $C_{2}$ . Then final potential difference across each will be

$\frac{C _{1} V _{1} + C _{2} V _{2}}{C _{1} + C _{2}}$

$(\frac{C _{1}}{C _{1} + C _{2}}) V$

$C_{1} + 2 C_{2}$

$(\frac{C _{1} + C _{2}}{C _{1} C _{2}}) V$