Question

A capacitor of capacitance $500\mu F$ is charged completely using a dc supply of $100V$. It is now connected to an inductor of inductance $50mH$ to form an LC circuit. The maximum current in LC circuit will be ____ $A$.

Answer 1

Answer: 10

Energy stored in capacitor
$=\frac{1}{2}C{V}^2=\frac{1}{2}500\times 10^{-6}\times 10^4$
$=\frac{5}{2}J$
Current will be maximum when whole energy of capacitor becomes energy of inductor.
$\frac{1}{2}L{I}^2=\frac{5}{2}$
$I=\sqrt{\frac{5}{L}}=\sqrt{\frac{5}{50\times 10^{-3}}}=10A.$