Question

A capacitor has capacitance $5\mu F$ when it's parallel plates are separated by air medium of thickness d. A slab of material of dielectric constant $1.5$ having area equal to that of plates but thickness $\frac{d}{2}$ is inserted between the plates. Capacitance of the capacitor in the presence of slab will be ___$\mu F$.

Answer 1

Answer: 6

$=\frac{{\in }_{0}A}{\left(\frac{d}{3}+\frac{d}{2}\right)}=\frac{6{\in }_{0}A}{5d}$
$=\frac{6}{5}\times 5\mu F=6\mu F$