Q. A cannon of mass 1000 kg, located at the base of an inclined plane fires a shell of mass 100 kg in a horizontal direction with a velocity 180 km/h. The angle of inclination of the inclined plane with the horizontal is . The coefficient of friction between the cannon and the inclined plane is 0.5. The height, in m, to which the cannon ascends the inclined plane as a result of the recoil is:

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Solution:

Given: Mass of shell Mass of cannon Velocity of shell Let velocity of cannon = v Hence, recoil velocity of cannon from conservation of momentum is The relation for the acceleration along inclined plane is The height to which the cannon ascends the inclined as a results of recoil, is given by (here )