A cane is taken out from a refrigerator at 0° C . The atmospheric temperature is 25° C . If t1 is the time taken to heat from 0° C to 5° C and t2 is the time taken from 10° C to 15° C , then

Question

A cane is taken out from a refrigerator at 0° C . The atmospheric temperature is 25° C . If t1 is the time taken to heat from 0° C to 5° C and t2 is the time taken from 10° C to 15° C , then (A)  t1>t2  (B)  t1<t2  (C)  t1=t2  (D) there is no relation

Tardigrade Admin · Accepted Answer

According to Newtons law of cooling t1 will be less than t2 .

Q. A cane is taken out from a refrigerator at $0^{\circ} C$ . The atmospheric temperature is $25^{\circ} C$ . If $t_{1}$ is the time taken to heat from $0^{\circ} C$ to $5^{\circ} C$ and $t_{2}$ is the time taken from $10^{\circ} C$ to $15^{\circ} C$ , then

$t_{1} > t_{2}$

$t_{1} < t_{2}$

$t_{1} = t_{2}$

there is no relation

According to Newtons law of cooling $t_{1}$ will be less than $t_{2}$ .

Q. A cane is taken out from a refrigerator at 0∘C . The atmospheric temperature is 25∘C . If t1​ is the time taken to heat from 0∘C to 5∘C and t2​ is the time taken from 10∘C to 15∘C , then

t1​>t2​

t1​<t2​

t1​=t2​