A [ C 6 H 10 O 3. (keto ester) ] -[ NaOH + I 2][Δ] yellow p p t + B -[ H +] C -[- C O 2][Δ] C H 3 C O O H. Hence, A is

Question

A [ C 6 H 10 O 3. (keto ester) ] ->[ NaOH + I 2][Δ] yellow p p t + B ->[ H +] C ->[- C O 2][Δ] C H 3 C O O H. Hence, A is (A) CH 3 overset underset||OCCH 2 overset underset||OCOC 2 H 5 (B) CH 3CH2 overset underset||OCCH 2 overset underset||OCOCH 3 (C) Both are correct (D) None is correct

Tardigrade Admin · Accepted Answer

' A ' gives iodoform test thus A has - overset underset||OC CH 3 group. ' C ' eliminates CO 2 on heating hence, C has two - COOH groups at same (gem) position. Since, only (a) has - overset underset||OCCH 3 group, therefore, compound ' A ' is CH 3 overset underset||OCCH 2 COC 2 H 5. <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/961207a080ee75c90c2804a01e4217ec-.png" />

Q. A $[C_{6} H_{10} O_{3}$ (keto ester) $] NaOH + I_{2} Δ$ yellow $ppt + B H^{+} C - C O_{2} Δ C H_{3} COO H$ . Hence, $A$ is

$C H_{3} C ∣∣ O C H_{2} C ∣∣ O O C_{2} H_{5}$

$C H_{3} C H_{2} C ∣∣ O C H_{2} C ∣∣ O OC H_{3}$

Both are correct

None is correct

' $A$ ' gives iodoform test thus $A$ has $- C ∣∣ O C H_{3}$ group. ' $C$ ' eliminates $C O_{2}$ on heating hence, $C$ has two $- COO H$ groups at same (gem) position.
Since, only (a) has $- C ∣∣ O C H_{3}$ group, therefore,
compound ' $A$ ' is $C H_{3} C ∣∣ O C H_{2} CO C_{2} H_{5}$ .

Q. A [C6​H10​O3​ (keto ester) ] NaOH+I2​Δ​ yellow ppt+B H+​C- CO2​Δ​CH3​COOH. Hence, A is

CH3​C∣∣O​CH2​C∣∣O​OC2​H5​

CH3​CH2​C∣∣O​CH2​C∣∣O​OCH3​