A bus begins to move with an acceleration of 1 ms-2 . A man who is 48 m behind the bus starts running at 10 ms-1 to catch the bus. The man will be able to catch the bus after

Question

A bus begins to move with an acceleration of 1 ms-2 . A man who is 48 m behind the bus starts running at 10 ms-1 to catch the bus. The man will be able to catch the bus after (A) 6s (B) 5 s (C) 3 s (D) 7 s

Tardigrade Admin · Accepted Answer

Given a=1 text ms-2, text s=48 text m By the equation of motion 40+(1/2)at2=10t t=8s

Q. A bus begins to move with an acceleration of $1 m s^{- 2}$ . A man who is $48 m$ behind the bus starts running at $10 m s^{- 1}$ to catch the bus. The man will be able to catch the bus after

6s

5 s

3 s

7 s

8s

Given $a = 1 m s^{- 2}, s = 48 m$
By the equation of motion
$40 + \frac{1}{2} a t^{2} = 10 t$
$t = 8 s$

Q. A bus begins to move with an acceleration of 1ms−2 . A man who is 48m behind the bus starts running at 10ms−1 to catch the bus. The man will be able to catch the bus after

6s

5 s

3 s

7 s

8s

Given a=1ms−2, s=48m By the equation of motion 40+21​at2=10t t=8s

Q. A bus begins to move with an acceleration of $1 m s^{- 2}$ . A man who is $48 m$ behind the bus starts running at $10 m s^{- 1}$ to catch the bus. The man will be able to catch the bus after

Given $a = 1 m s^{- 2}, s = 48 m$
By the equation of motion
$40 + \frac{1}{2} a t^{2} = 10 t$
$t = 8 s$