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  4. A bus begins to move with an acceleration of 1 ms-2 . A man who is 48 m behind the bus starts running at 10 ms-1 to catch the bus. The man will be able to catch the bus after

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Q. A bus begins to move with an acceleration of $ 1\,\,m{{s}^{-2}} $ . A man who is $48\,m$ behind the bus starts running at $10\, ms^{-1}$ to catch the bus. The man will be able to catch the bus after

KEAMKEAM 2011Motion in a Straight Line

Solution:

Given $ a=1\text{ }m{{s}^{-2}},\text{ s}=48\text{ }m $
By the equation of motion
$ 40+\frac{1}{2}a{{t}^{2}}=10t $
$ t=8s $