A bullet of mass 70 gm travelling at 250 m / s strikes and gets embedded in ice at 0° C. Assuming that temperature of bullet does not change, find the amount of ice that melts. (Assume all energy lost melts ice)

Question

A bullet of mass 70 gm travelling at 250 m / s strikes and gets embedded in ice at 0° C. Assuming that temperature of bullet does not change, find the amount of ice that melts. (Assume all energy lost melts ice) (A) (2/127) kg (B) (3/424) kg (C) (5/768) kg (D) (7000/256) kg

Tardigrade Admin · Accepted Answer

(1/2) × 70 × 10-3 × 2502= m × L = m × 80 × 4.2 × 103 ⇒ m =(5/768) kg

Q. A bullet of mass $70 g m$ travelling at $250 m / s$ strikes and gets embedded in ice at $0^{\circ} C$ . Assuming that temperature of bullet does not change, find the amount of ice that melts. (Assume all energy lost melts ice)

$\frac{2}{127} k g$

$\frac{3}{424} k g$

$\frac{5}{768} k g$

$\frac{7000}{256} k g$

$\frac{1}{2} \times 70 \times 1 0^{- 3} \times 25 0^{2} = m \times L$
$= m \times 80 \times 4.2 \times 1 0^{3}$
$\Rightarrow m = \frac{5}{768} k g$

Q. A bullet of mass 70gm travelling at 250m/s strikes and gets embedded in ice at 0∘C. Assuming that temperature of bullet does not change, find the amount of ice that melts. (Assume all energy lost melts ice)

1272​kg

4243​kg

7685​kg

2567000​kg