The bullet performs a horizontal journey of 100cm with constant velocity of 1500m/s. The bullet also performs a vertical journey of h with zero initial velocity and downward acceleration g. ∴ For horizontal journey, time (t)= Velocity Distance ∴t=1500100=151sec....(1)
The bullet performs vertical journey for this time.
For vertical journey, h=ut+21gt2 h=0+21×10×(151)2 or, h=920cm=2.2cm