A bullet of mass 4 g is fired horizontally with a speed of 300 m/ s into 0.8 kg block of wood at rest on a table. If the coefficient of friction between the block and the table is 0.3, how far will the block slide approximately ?

Question

A bullet of mass 4 g is fired horizontally with a speed of 300 m/ s into 0.8 kg block of wood at rest on a table. If the coefficient of friction between the block and the table is 0.3, how far will the block slide approximately ? (A) 0.19 m (B) 0.379 m (C) 0.569 m (D) 0.758 m

Tardigrade Admin · Accepted Answer

If v is speed gained by block (4/1000) × 300=0.8 × v v =(3/2) m / s ∴ (1/2) × 0.8 ×((3/2))2=0.3 × 0.8 × 10 × x ⇒ x =0.379 m

Q. A bullet of mass $4 g$ is fired horizontally with a speed of $300 m / s$ into $0.8 k g$ block of wood at rest on a table. If the coefficient of friction between the block and the table is $0.3$ , how far will the block slide approximately ?

0.19 m

0.379 m

0.569 m

0.758 m

If $v$ is speed gained by block
$\frac{4}{1000} \times 300 = 0.8 \times v$
$v = \frac{3}{2} m / s$
$∴ \frac{1}{2} \times 0.8 \times (\frac{3}{2})^{2} = 0.3 \times 0.8 \times 10 \times x$
$\Rightarrow x = 0.379 m$

Q. A bullet of mass 4g is fired horizontally with a speed of 300m/s into 0.8kg block of wood at rest on a table. If the coefficient of friction between the block and the table is 0.3, how far will the block slide approximately ?