A bulb contains one mole of hydrogen mixed with one mole of oxygen at temperature T. The ratio of r.m.s. values of velocity of hydrogen molecules to that of oxygen molecules, is

Question

A bulb contains one mole of hydrogen mixed with one mole of oxygen at temperature T. The ratio of r.m.s. values of velocity of hydrogen molecules to that of oxygen molecules, is (A) 4: 1 (B) 1: 16 (C) 1: 4 (D) 16: 1

Tardigrade Admin · Accepted Answer

Given: One mole of hydrogen mixed with one mole of oxygen. We know that r.m.s. velocity (vrms)=√(3RT/M)μ √(1/M) or ((vrms)H/(vrms)O)=√(MO/MH)=√(32/2)=(4/1). or (vrms)H: (vrms)O= 4: 1.

Q. A bulb contains one mole of hydrogen mixed with one mole of oxygen at temperature $T$ . The ratio of $r . m . s .$ values of velocity of hydrogen molecules to that of oxygen molecules, is

4 : 1

1 : 16

1 : 4

16 : 1

Given: One mole of hydrogen mixed with one mole of oxygen.
We know that r.m.s. velocity
$(v_{r m s}) = \frac{3 RT}{M} μ \frac{1}{M}$
or $\frac{( v _{r m s} ) _{H}}{( v _{r m s} ) _{O}} = \frac{M _{O}}{M _{H}} = \frac{32}{2} = \frac{4}{1} .$
or $(v_{r m s})_{H} : (v_{r m s})_{_{O}} = 4 : 1.$

Q. A bulb contains one mole of hydrogen mixed with one mole of oxygen at temperature T. The ratio of r.m.s. values of velocity of hydrogen molecules to that of oxygen molecules, is