A bridge is in the form of a semi-circle of radius 40. The greatest speed with which a motor cycle can cross the bridge without leaving the ground at the highest point is (g=10 ms-2) (Frictional force is negligibly small)

Question

A bridge is in the form of a semi-circle of radius 40. The greatest speed with which a motor cycle can cross the bridge without leaving the ground at the highest point is (g=10 ms-2) (Frictional force is negligibly small) (A)  40 ms-1  (B)  20 ms-1  (C)  30 ms-1  (D)  15 ms-1

Tardigrade Admin · Accepted Answer

Given r=40 text m and g=10 text ms-2 We have v=√gr =√10× 40 =√400 =20 text ms-1

Q. A bridge is in the form of a semi-circle of radius $40$ . The greatest speed with which a motor cycle can cross the bridge without leaving the ground at the highest point is $(g = 10 m s^{- 2})$ (Frictional force is negligibly small)

$40 m s^{- 1}$

$20 m s^{- 1}$

$30 m s^{- 1}$

$15 m s^{- 1}$

$25 m s^{- 1}$

Given $r = 40 m$ and $g = 10 m s^{- 2}$
We have $v = g r$
$= 10 \times 40$
$= 400$ $= 20 m s^{- 1}$

Q. A bridge is in the form of a semi-circle of radius 40. The greatest speed with which a motor cycle can cross the bridge without leaving the ground at the highest point is (g=10ms−2) (Frictional force is negligibly small)

40ms−1

20ms−1

30ms−1

15ms−1

25ms−1

Given r=40m and g=10ms−2 We have v=gr​ =10×40​ =400​ =20ms−1