A boy weighing 50 kg eat some bananas. The energy content of the bananas is 1000 cal . If the boy uses all of this energy to jump upwards from the ground, then the height up to which his centre of mass will rise is [mechanical equivalent of heat = 4.2 J cal- 1 , g=10 m s- 2 ]

Question

A boy weighing 50 kg eat some bananas. The energy content of the bananas is 1000 cal . If the boy uses all of this energy to jump upwards from the ground, then the height up to which his centre of mass will rise is [mechanical equivalent of heat = 4.2 J cal- 1 , g=10 m s- 2 ] (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Energy used by the boy is E=1000× 4.2 J ⇒ 4200=50× 10× h ⇒ h=8.4 m

Q. A boy weighing $50 k g$ eat some bananas. The energy content of the bananas is $1000 c a l$ . If the boy uses all of this energy to jump upwards from the ground, then the height up to which his centre of mass will rise is [mechanical equivalent of heat = $4.2 J c a l^{- 1}$ , $g = 10 m s^{- 2}$ ]

Energy used by the boy is
$E = 1000 \times 4.2 J$
$\Rightarrow 4200 = 50 \times 10 \times h$
$\Rightarrow h = 8.4 m$

Q. A boy weighing 50kg eat some bananas. The energy content of the bananas is 1000cal . If the boy uses all of this energy to jump upwards from the ground, then the height up to which his centre of mass will rise is [mechanical equivalent of heat = 4.2Jcal−1 , g=10ms−2 ]

Energy used by the boy is E=1000×4.2J ⇒4200=50×10×h ⇒h=8.4m

Energy used by the boy is
$E = 1000 \times 4.2 J$
$\Rightarrow 4200 = 50 \times 10 \times h$
$\Rightarrow h = 8.4 m$