A boy runs towards a man standing 150 m away. Speed of boy is 5 m s-1 and that of man is 10 ms-1 The time and distance of their meeting from the boy's position are

Question

A boy runs towards a man standing 150 m away. Speed of boy is 5 m s-1 and that of man is 10 ms-1 The time and distance of their meeting from the boy's position are (A) 15 s (B) 5 s, 150 m (C) 10 s, 50 m (D) 10 s,100 m

Tardigrade Admin · Accepted Answer

The relative speed = 5 + 10 = 15 m s-1 But relative speed = (Distance/time) i.e. Time = (Distance/relative speed) = (150/15) = 10 s Distance from boy's position = velocity of boy x time = 5 × 10 = 50m

Q. A boy runs towards a man standing $150 m$ away. Speed of boy is $5 m s^{- 1}$ and that of man is $10 m s^{- 1}$ The time and distance of their meeting from the boy's position are

15 s

5 s, 150 m

10 s, 50 m

10 s,100 m

The relative speed = 5 + 10 = 15 m $s^{- 1}$ But relative speed = $\frac{D i s t an ce}{t im e}$ i.e. Time = $\frac{D i s t an ce}{re l a t i v e s p ee d} = \frac{150}{15} = 10 s$ Distance from boy's position = velocity of boy x time = 5 $\times$ 10 = 50m

Q. A boy runs towards a man standing 150m away. Speed of boy is 5ms−1 and that of man is 10ms−1 The time and distance of their meeting from the boy's position are