Question

A boy pushes a box of mass $2kg$ with a force $\vec{F}=(20\hat{i}+10\hat{j})N$ on a frictionless surface. If the box was initially at rest, then ______$m$ is displacement along the $x$ -axis after $10s$

Answer 1

Answer: 500

$\vec{F}=20\hat{i}+10\hat{j}$
$\vec{a}=\frac{\vec{F}}{m}=\frac{20\hat{i}+10\hat{j}}{2}$
$\Rightarrow 10\hat{i}+5\hat{j}$
$\therefore \vec{s}=\frac{1}{2}\vec{a}{t}^2=\frac{1}{2}(10\hat{i}+5\hat{j})\times (10{)}^2$
$\Rightarrow 50(10\hat{i}+5\hat{j})m$
$\therefore$ Displacement along $x$ -axis
$\Rightarrow 50\times 10$
$\Rightarrow 500m$