Question

A boy pushes a box of mass $2\, kg$ with a force $\vec{ F }=(20 \hat{ i }+10 \hat{ j }) N$ on a frictionless surface. If the box was initially at rest, then ______$m$ is displacement along the $x$ -axis after $10\, s$

Answer 1

$\vec{ F }=20 \hat{ i }+10 \hat{ j }$
$\vec{ a }=\frac{\vec{ F }}{ m }=\frac{20 \hat{ i }+10 \hat{ j }}{2}$
$ \Rightarrow 10 \hat{ i }+5 \hat{ j }$
$\therefore \vec{ s }=\frac{1}{2} \vec{ a } t ^{2}=\frac{1}{2}(10 \hat{ i }+5 \hat{ j }) \times(10)^{2}$
$\Rightarrow 50(10 \hat{ i }+5 \hat{ j }) m$
$\therefore $ Displacement along $x$ -axis
$\Rightarrow 50 \times 10$
$ \Rightarrow 500 \,m$