A boy of 50 kg is standing in a left moving down with acceleration 9.8 m/s2 . The apparent weight of the boy is:

Question

A boy of 50 kg is standing in a left moving down with acceleration 9.8 m/s2 . The apparent weight of the boy is: (A)  (50/9.8)N  (B)  50× 9.8 N  (C) 50 N (D) zero

Tardigrade Admin · Accepted Answer

Mass of the boy m=50 Acceleration of lift (downwards) a=9.8 m / s 2 The apparent weight of the boy when the lift is moving downwards w=m(g-a)=50(9.8-9.8)=0

Q. A boy of $50 k g$ is standing in a left moving down with acceleration $9.8 m / s^{2}$ . The apparent weight of the boy is:

$\frac{50}{9.8} N$

$50 \times 9.8 N$

$50 N$

zero

Mass of the boy $m = 50$
Acceleration of lift (downwards)
$a = 9.8 m / s^{2}$
The apparent weight of the boy when the lift is moving downwards
$w = m (g - a) = 50 (9.8 - 9.8) = 0$

Q. A boy of 50kg is standing in a left moving down with acceleration 9.8m/s2 . The apparent weight of the boy is:

9.850​N

50×9.8N

50N