A boy is throwing stones at a target. The probability of hitting the target at any trial is (1/2) .The probability of hitting the target 5th time at the 10th throw is :

Question

A boy is throwing stones at a target. The probability of hitting the target at any trial is (1/2) .The probability of hitting the target 5th time at the 10th throw is : (A) (5/210) (B) (63/29) (C) (10C5/210) (D) None

Tardigrade Admin · Accepted Answer

The probability of hitting the target 5 text th time at the 10 text th throw = (the probability of hitting the target 4 times in the first 9 throws) × (the probability of hitting the target at the 10 text th throw) = 9 C4((1/2))9 × (1/2) = 9 C4((1/2))10 =(9.8 .7 .6/(1.2 .3 .4) 210)=(63/29)

Q. A boy is throwing stones at a target. The probability of hitting the target at any trial is $\frac{1}{2}$ .The probability of hitting the target $5^{t h}$ time at the $1 0^{t h}$ throw is :

$\frac{5}{2 ^{10}}$

$\frac{63}{2 ^{9}}$

$\frac{^{10} C _{5}}{2 ^{10}}$

None

Q. A boy is throwing stones at a target. The probability of hitting the target at any trial is 21​ .The probability of hitting the target 5th time at the 10th throw is :

2105​

2963​

21010C5​​

None

The probability of hitting the target 5th time at the 10th throw = (the probability of hitting the target 4 times in the first 9 throws) × (the probability of hitting the target at the 10th throw) =9C4​(21​)9×21​ =9C4​(21​)10 =(1.2.3.4)2109.8.7.6​=2963​

Q. A boy is throwing stones at a target. The probability of hitting the target at any trial is $\frac{1}{2}$ .The probability of hitting the target $5^{t h}$ time at the $1 0^{t h}$ throw is :

$\frac{5}{2 ^{10}}$

$\frac{63}{2 ^{9}}$

$\frac{^{10} C _{5}}{2 ^{10}}$