Q.
A bolt of mass 0.2kg falls from the ceiling of an elevator moving down with an uniform speed of 5ms−1. It hits the floor of the elevator (length of the elevator =5m) and does not rebound. The amount of heat produced by the impact is (Take g=10ms−2)
Here, m=0.2kg, v=5ms−1 h= length of elevator =5m
As relative velocity of the bolt w.r.t. elevator is zero, therefore, in the impact, only potential energy of the bolt is converted into heat energy.
Amount of heat produced = Potential energy lost by the bolt =mgh=(0.2kg)(10ms−2)(5m)=10J