A body thrown upwards with some velocity reaches the maximum height of 50 m. Another body with double the mass thrown up with four times the initial velocity will reach a maximum height of:

Question

A body thrown upwards with some velocity reaches the maximum height of 50 m. Another body with double the mass thrown up with four times the initial velocity will reach a maximum height of: (A) 600 m (B) 200 m (C) 800 m (D) 100 m

Tardigrade Admin · Accepted Answer

v2=u2-2 g s ⇒ 0=u2-2 g s u 2=2 gs ⇒ u 2 propto S Motion under gravity is independent of mass ( u 2/16 u 2)=(50/ h ) h =16 × 50 h =800 m

Q. A body thrown upwards with some velocity reaches the maximum height of $50 m$ . Another body with double the mass thrown up with four times the initial velocity will reach a maximum height of:

600 m

200 m

800 m

100 m

$v^{2} = u^{2} - 2 g s \Rightarrow 0 = u^{2} - 2 g s$
$u^{2} = 2 g s \Rightarrow u^{2} \propto S$
Motion under gravity is independent of mass
$\frac{u ^{2}}{16 u ^{2}} = \frac{50}{h}$
$h = 16 \times 50$
$h = 800 m$

Q. A body thrown upwards with some velocity reaches the maximum height of 50m. Another body with double the mass thrown up with four times the initial velocity will reach a maximum height of: