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Q. A body thrown upwards with some velocity reaches the maximum height of $50 \,m$. Another body with double the mass thrown up with four times the initial velocity will reach a maximum height of:

Motion in a Straight Line

Solution:

$v^{2}=u^{2}-2 g s \Rightarrow 0=u^{2}-2 g s$
$u ^{2}=2 gs \Rightarrow u ^{2} \propto S$
Motion under gravity is independent of mass
$\frac{ u ^{2}}{16 u ^{2}}=\frac{50}{ h }$
$h =16 \times 50$
$h =800\, m$