A body starts with initial velocity u and moves with uniform acceleration when the velocity has increased to 5u, the acceleration is reversed in direction, the magnitude remaining constant. The velocity when it returns to starting point

Question

A body starts with initial velocity u and moves with uniform acceleration when the velocity has increased to 5u, the acceleration is reversed in direction, the magnitude remaining constant. The velocity when it returns to starting point (A) -7u (B) -5u (C) -2u (D) 2u

Tardigrade Admin · Accepted Answer

((5 u)2-v2/v2-(5 u)2)=(2 a s/2 a s) v=7 u, barv=-7 u

Q. A body starts with initial velocity $u$ and moves with uniform acceleration when the velocity has increased to $5 u$ , the acceleration is reversed in direction, the magnitude remaining constant. The velocity when it returns to starting point

-7u

-5u

-2u

2u

$\frac{( 5 u ) ^{2} - v ^{2}}{v ^{2} - ( 5 u ) ^{2}} = \frac{2 a s}{2 a s}$
$v = 7 u, \overset{v}{ˉ} = - 7 u$

Q. A body starts with initial velocity u and moves with uniform acceleration when the velocity has increased to 5u, the acceleration is reversed in direction, the magnitude remaining constant. The velocity when it returns to starting point

-7u

-5u

-2u

2u

v2−(5u)2(5u)2−v2​=2as2as​ v=7u,vˉ=−7u

Q. A body starts with initial velocity $u$ and moves with uniform acceleration when the velocity has increased to $5 u$ , the acceleration is reversed in direction, the magnitude remaining constant. The velocity when it returns to starting point

$\frac{( 5 u ) ^{2} - v ^{2}}{v ^{2} - ( 5 u ) ^{2}} = \frac{2 a s}{2 a s}$
$v = 7 u, \overset{v}{ˉ} = - 7 u$