A body starts from rest travels a distance x in first two seconds and a distance y in next two seconds. The relation between x and y is

Question

A body starts from rest travels a distance x in first two seconds and a distance y in next two seconds. The relation between x and y is (A) y = 4 x (B) y = x (C) y=3 x (D) y=2 x

Tardigrade Admin · Accepted Answer

If particle starts from rest and moves with constant acceleration then in successive equal interval of time the ratio of distance covered by it will be:

1 : 2 : 5 : 7 \dots\dots (2 n - 1)

i.e., ratio of

x

and

y

will

b 1 : 3

i.e.,

\frac{x}{y} = \frac{1}{3} \Rightarrow y = 3 x

Q. A body starts from rest travels a distance x in first two seconds and a distance y in next two seconds. The relation between x and y is

y = 4 x

y = x

y=3 x

y=2 x

If particle starts from rest and moves with constant acceleration then in successive equal interval of time the ratio of distance covered by it will be: 1:2:5:7……(2n−1) i.e., ratio of x and y will b1:3 i.e., yx​=31​⇒y=3x

Q. A body starts from rest travels a distance $x$ in first two seconds and a distance $y$ in next two seconds. The relation between $x$ and $y$ is

If particle starts from rest and moves with constant acceleration then in successive equal interval of time the ratio of distance covered by it will be:
$1 : 2 : 5 : 7 \dots\dots (2 n - 1)$
i.e., ratio of $x$ and $y$ will $b 1 : 3$ i.e., $\frac{x}{y} = \frac{1}{3} \Rightarrow y = 3 x$