Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Physics
A body starts from rest and travels 120 cm in 6th second. The acceleration of the body is
Q. A body starts from rest and travels
120
c
m
in
6
t
h
second. The acceleration of the body is
2771
223
Motion in a Straight Line
Report Error
A
0.2
m
s
−
2
17%
B
0.27
m
s
−
2
13%
C
0.218
m
s
−
2
60%
D
0.3
m
s
−
2
10%
Solution:
Using
S
n
=
u
+
2
1
a
(
2
n
−
1
)
, we get
S
6
=
u
+
2
a
(
2
×
6
−
1
)
i.e. 1.2 = 0 +
2
a
(
11
)
i
.
e
.
a
=
0.218
m
s
−
2