A body of volume 100 cc floats immersed completely in water contained a jar. The weight of water and jar before immersion of the body was 700 g. After immersion weight of water and jar will be:

Question

A body of volume 100 cc floats immersed completely in water contained a jar. The weight of water and jar before immersion of the body was 700 g. After immersion weight of water and jar will be: (A) 500 g (B) 700 g (C) 100 g (D) 800 g

Tardigrade Admin · Accepted Answer

As the body floats completely immersed in water,
Hence

W_{body} = W_{displaced water}

= weight of

100 cc

of water
Or mass of body

=

mass of

100 cc

of water

= 100 g

Hence, total mass

= 700 g + 100 g = 800 g_{.}

Q. A body of volume 100cc floats immersed completely in water contained a jar. The weight of water and jar before immersion of the body was 700g. After immersion weight of water and jar will be:

500 g

700 g

100 g

800 g

As the body floats completely immersed in water, Hence Wbody ​=Wdisplaced water ​ = weight of 100cc of water Or mass of body = mass of 100cc of water =100g Hence, total mass =700g+100g=800g. ​

Q. A body of volume $100 cc$ floats immersed completely in water contained a jar. The weight of water and jar before immersion of the body was $700 g$ . After immersion weight of water and jar will be:

As the body floats completely immersed in water,
Hence $W_{body} = W_{displaced water}$
= weight of $100 cc$ of water
Or mass of body $=$ mass of $100 cc$ of water $= 100 g$
Hence, total mass $= 700 g + 100 g = 800 g_{.}$