A body of mass m, is moving with velocity upsilon. It collides with another stationary ball of mass m2. They get embedded. At the point of collision, 'velocity' of the system will

Question

A body of mass m, is moving with velocity upsilon. It collides with another stationary ball of mass m2. They get embedded. At the point of collision, 'velocity' of the system will (A) increase (B) decrease but not to zero (C) zero (D) remain the same.

Tardigrade Admin · Accepted Answer

Just before the collision the velocity of the center of mass will be

u =

\frac{m _{1} \times V + m _{2} \times 0}{m _{1} + m _{2}} = \frac{m _{1}}{m _{1} + m _{2}} V

after the collision if the system moves with velocity

V_{0}

then on conserving the momentum
we will get

m_{1} V + 0 = (m_{1} + m_{2}) V_{0}

or

V_{0} = \frac{m _{1}}{m _{1} + m - 2} V

we can notice that both

V_{0}

and

u

are same, due to absence of external force on the system.

Q. A body of mass m, is moving with velocity υ. It collides with another stationary ball of mass m2​. They get embedded. At the point of collision, 'velocity' of the system will

increase

decrease but not to zero

zero

remain the same.

Q. A body of mass $m$ , is moving with velocity $υ$ . It collides with another stationary ball of mass $m_{2}$ . They get embedded. At the point of collision, 'velocity' of the system will