A body of mass m collides against a wall with the velocity v and rebounds with the same speed. Its magnitude of change of momentum is

Question

A body of mass m collides against a wall with the velocity v and rebounds with the same speed. Its magnitude of change of momentum is (A) 2m v (B) m v (C) (1/2)m v (D) 0

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-h5cjykhvysrpxywh.jpg" /> Change in momentum Δ p=pf-pi Δ p=mv-(- m v) Δ p=2mv

Q. A body of mass $m$ collides against a wall with the velocity $v$ and rebounds with the same speed. Its magnitude of change of momentum is

$2 m v$

$m v$

$\frac{1}{2} m v$

0

Change in momentum
$Δ p = p_{f} - p_{i}$
$Δ p = m v - (- m v)$
$Δ p = 2 m v$

Q. A body of mass m collides against a wall with the velocity v and rebounds with the same speed. Its magnitude of change of momentum is

2mv

mv

21​mv

0

Change in momentum Δp=pf​−pi​ Δp=mv−(−mv) Δp=2mv

Q. A body of mass $m$ collides against a wall with the velocity $v$ and rebounds with the same speed. Its magnitude of change of momentum is

$2 m v$

$m v$

$\frac{1}{2} m v$

Change in momentum
$Δ p = p_{f} - p_{i}$
$Δ p = m v - (- m v)$
$Δ p = 2 m v$