A body of mass 5 kg starts from the origin with an initial velocity u=30 hat i +40 hat j m s-1. If a constant force -6 hati-5 hatj N acts on the body, the time (in seconds) in which the y component of the velocity becomes zero is

Question

A body of mass 5 kg starts from the origin with an initial velocity u=30 hat i +40 hat j m s-1. If a constant force -6 hati-5 hatj N acts on the body, the time (in seconds) in which the y component of the velocity becomes zero is (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

From Newton's second law of motion, Fy=( triangle Py/ triangle t) triangle t=( triangle Py/Fy) =(0-(5 × 40)/-5)=40 s

Q. A body of mass $5 k g$ starts from the origin with an initial velocity $u = 30 \hat{i} + 40 \hat{j}$ $m s^{- 1}$ . If a constant force $- 6 \hat{i} - 5 \hat{j} N$ acts on the body, the time (in seconds) in which the $y$ component of the velocity becomes zero is

From Newton's second law of motion,
$F_{y} = \frac{△ P _{y}}{△ t}$
$△ t = \frac{△ P _{y}}{F _{y}}$
$= \frac{0 - ( 5 \times 40 )}{- 5} = 40 s$

Q. A body of mass 5kg starts from the origin with an initial velocity u=30i^+40j^​ ms−1. If a constant force −6i^−5j^​N acts on the body, the time (in seconds) in which the y component of the velocity becomes zero is

From Newton's second law of motion, Fy​=△t△Py​​ △t=Fy​△Py​​ =−50−(5×40)​=40s

Q. A body of mass $5 k g$ starts from the origin with an initial velocity $u = 30 \hat{i} + 40 \hat{j}$ $m s^{- 1}$ . If a constant force $- 6 \hat{i} - 5 \hat{j} N$ acts on the body, the time (in seconds) in which the $y$ component of the velocity becomes zero is

From Newton's second law of motion,
$F_{y} = \frac{△ P _{y}}{△ t}$
$△ t = \frac{△ P _{y}}{F _{y}}$
$= \frac{0 - ( 5 \times 40 )}{- 5} = 40 s$