A body of mass 5 kg is suspended by a spring balance on an inclined plane as shown in figure. The spring balance measure :

Question

A body of mass 5 kg is suspended by a spring balance on an inclined plane as shown in figure. The spring balance measure : (A) 50 N (B) 25 N (C) 500 N (D) 10 N

Tardigrade Admin · Accepted Answer

Acceleration of the body down the rough inclined plane =g sin θ Force applied on spring balance =mg sin θ =5 × 10 × sin 30° =5 × 10 × (1/2)=25 N

Q. A body of mass $5 k g$ is suspended by a spring balance on an inclined plane as shown in figure. The spring balance measure :

50 N

25 N

500 N

10 N

Acceleration of the body down the rough inclined plane $= g sin θ$
Force applied on spring balance
$= m g sin θ$
$= 5 \times 10 \times sin 3 0^{\circ}$
$= 5 \times 10 \times \frac{1}{2} = 25 N$

Q. A body of mass 5kg is suspended by a spring balance on an inclined plane as shown in figure. The spring balance measure :