A body of mass 5 kg is acted on by a force F which varies with time t as shown in the given figure. Then the momentum gained by the body at the end of 10 seconds is

Question

A body of mass 5 kg is acted on by a force F which varies with time t as shown in the given figure. Then the momentum gained by the body at the end of 10 seconds is (A) 0 kg m s-1 (B) 100 kg m s-1 (C) 140 kg m s-1 (D) 200 kg m s-1

Tardigrade Admin · Accepted Answer

Change in momentum = force × time = area of trapezium OABC = (1/2) (10 + 4) × 20 = 14 kg m s-1

Q. A body of mass 5 kg is acted on by a force F which varies with time $t$ as shown in the given figure. Then the momentum gained by the body at the end of 10 seconds is

$0 k g m s^{- 1}$

$100 k g m s^{- 1}$

$140 k g m s^{- 1}$

$200 k g m s^{- 1}$

Change in momentum = force $\times$ time
= area of trapezium $O A BC$
$= \frac{1}{2} (10 + 4) \times 20 = 14 k g m s^{- 1}$

Q. A body of mass 5 kg is acted on by a force F which varies with time t as shown in the given figure. Then the momentum gained by the body at the end of 10 seconds is

0kgms−1

100kgms−1

140kgms−1

200kgms−1