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Physics
A body of mass 5 kg is acted on by a force F which varies with time t as shown in the given figure. Then the momentum gained by the body at the end of 10 seconds is
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Q. A body of mass 5 kg is acted on by a force F which varies with time $t$ as shown in the given figure. Then the momentum gained by the body at the end of 10 seconds is
JIPMER
JIPMER 2010
Laws of Motion
A
$0\, kg \, m \, s^{-1}$
5%
B
$100\, kg \, m \, s^{-1}$
11%
C
$140\, kg \, m \, s^{-1}$
78%
D
$200\, kg \, m \, s^{-1}$
6%
Solution:
Change in momentum = force $\times$ time
= area of trapezium $OABC$
$= \frac{1}{2} (10 + 4) \times 20 = 14 kg \, m \, s^{-1}$