A body of mass 2 kg is kept by pressing to a vertical wall by a force of 100 N . The friction between wall and body is 0.3 . Then the frictional force is equal to

Question

A body of mass 2 kg is kept by pressing to a vertical wall by a force of 100 N . The friction between wall and body is 0.3 . Then the frictional force is equal to (A) 6 N (B) 20 N (C) 600 N (D) 700 N

Tardigrade Admin · Accepted Answer

Given, mass of body = 2 kg According to question, ∵ Friction force due to 100 N f=MR=0.3×100=30 N but force due to gravitation, F=mg=2× 10=20 N So, there is no acceleration in box i.e. a=0 Hence, friction force wiill be f=200 N

Q. A body of mass $2 k g$ is kept by pressing to a vertical wall by a force of $100 N$ . The friction between wall and body is $0.3$ . Then the frictional force is equal to

6 N

20 N

600 N

700 N

Given, mass of body = $2 k g$
According to question,
$∵$ Friction force due to $100 N$
$f = MR = 0.3 \times 100 = 30 N$
but force due to gravitation,
$F = m g = 2 \times 10 = 20 N$
So, there is no acceleration in box i.e. $a = 0$
Hence, friction force wiill be $f = 200 N$

Q. A body of mass 2kg is kept by pressing to a vertical wall by a force of 100N . The friction between wall and body is 0.3 . Then the frictional force is equal to

6 N

20 N

600 N

700 N

Given, mass of body = 2kg According to question, ∵ Friction force due to 100N f=MR=0.3×100=30N but force due to gravitation, F=mg=2×10=20N So, there is no acceleration in box i.e. a=0 Hence, friction force wiill be f=200N

Q. A body of mass $2 k g$ is kept by pressing to a vertical wall by a force of $100 N$ . The friction between wall and body is $0.3$ . Then the frictional force is equal to

Given, mass of body = $2 k g$
According to question,
$∵$ Friction force due to $100 N$
$f = MR = 0.3 \times 100 = 30 N$
but force due to gravitation,
$F = m g = 2 \times 10 = 20 N$
So, there is no acceleration in box i.e. $a = 0$
Hence, friction force wiill be $f = 200 N$